4(c-2)+3=2+c-7

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Solution for 4(c-2)+3=2+c-7 equation: 



4(c-2)+3=2+c-7

We move all terms to the left:

4(c-2)+3-(2+c-7)=0

We add all the numbers together, and all the variables

4(c-2)-(c-5)+3=0

We multiply parentheses

4c-(c-5)-8+3=0

We get rid of parentheses

4c-c+5-8+3=0

We add all the numbers together, and all the variables

3c=0

c=0/3

c=0

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