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p2-85p+900=0
We add all the numbers together, and all the variables
p^2-85p+900=0
a = 1; b = -85; c = +900;
Δ = b2-4ac
Δ = -852-4·1·900
Δ = 3625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3625}=\sqrt{25*145}=\sqrt{25}*\sqrt{145}=5\sqrt{145}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-5\sqrt{145}}{2*1}=\frac{85-5\sqrt{145}}{2} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+5\sqrt{145}}{2*1}=\frac{85+5\sqrt{145}}{2} $
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