2(3y+1)+4y=12

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Solution for 2(3y+1)+4y=12 equation: 



2(3y+1)+4y=12

We move all terms to the left:

2(3y+1)+4y-(12)=0

We add all the numbers together, and all the variables

4y+2(3y+1)-12=0

We multiply parentheses

4y+6y+2-12=0

We add all the numbers together, and all the variables

10y-10=0

We move all terms containing y to the left, all other terms to the right

10y=10

y=10/10

y=1

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