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0.01x^2-0.4x+4=0
a = 0.01; b = -0.4; c = +4;
Δ = b2-4ac
Δ = -0.42-4·0.01·4
Δ = 2.7755575615629E-17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.4)-\sqrt{2.7755575615629E-17}}{2*0.01}=\frac{0.4-\sqrt{2.7755575615629E-17}}{0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.4)+\sqrt{2.7755575615629E-17}}{2*0.01}=\frac{0.4+\sqrt{2.7755575615629E-17}}{0.02} $
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