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n2-18n-30=0
We add all the numbers together, and all the variables
n^2-18n-30=0
a = 1; b = -18; c = -30;
Δ = b2-4ac
Δ = -182-4·1·(-30)
Δ = 444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{444}=\sqrt{4*111}=\sqrt{4}*\sqrt{111}=2\sqrt{111}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{111}}{2*1}=\frac{18-2\sqrt{111}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{111}}{2*1}=\frac{18+2\sqrt{111}}{2} $
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