x*(-4x)=(2x+1)(3-2x)

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Solution for x*(-4x)=(2x+1)(3-2x) equation: 



x(-4x)=(2x+1)(3-2x)

We move all terms to the left:

x(-4x)-((2x+1)(3-2x))=0

We add all the numbers together, and all the variables

x(-4x)-((2x+1)(-2x+3))=0

We multiply parentheses

-4x^2-((2x+1)(-2x+3))=0

We multiply parentheses ..

-4x^2-((-4x^2+6x-2x+3))=0



We calculate terms in parentheses: -((-4x^2+6x-2x+3)), so:

(-4x^2+6x-2x+3)

We get rid of parentheses

-4x^2+6x-2x+3

We add all the numbers together, and all the variables

-4x^2+4x+3

Back to the equation:

-(-4x^2+4x+3)



We get rid of parentheses

-4x^2+4x^2-4x-3=0

We add all the numbers together, and all the variables

-4x-3=0

We move all terms containing x to the left, all other terms to the right

-4x=3

x=3/-4

x=-3/4

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