n+12/4=n/16n=

Solution for n+12/4=n/16n= equation:

n+12/4=n/16n=

We move all terms to the left:

n+12/4-(n/16n)=0


Domain of the equation: 16n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

n-(+n/16n)+12/4=0

We add all the numbers together, and all the variables

n-(+n/16n)+3=0

We get rid of parentheses

n-n/16n+3=0

We multiply all the terms by the denominator


n*16n-n+3*16n=0

We add all the numbers together, and all the variables

-1n+n*16n+3*16n=0

Wy multiply elements

16n^2-1n+48n=0

We add all the numbers together, and all the variables

16n^2+47n=0

a = 16; b = 47; c = 0;
Δ = b2-4ac
Δ = 472-4·16·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-47}{2*16}=\frac{-94}{32}
=-2+15/16
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+47}{2*16}=\frac{0}{32}
=0
$