3x(4x)(72-3x-4x)=96

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Solution for 3x(4x)(72-3x-4x)=96 equation: 



3x(4x)(72-3x-4x)=96

We move all terms to the left:

3x(4x)(72-3x-4x)-(96)=0

We add all the numbers together, and all the variables

3x4x(-7x+72)-96=0

We multiply parentheses

-21x^5+216x^4-96=0

We do not support expression: x^5

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