(2m+5)(m-5)=-2m(14m+11)-32

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Solution for (2m+5)(m-5)=-2m(14m+11)-32 equation: 



(2m+5)(m-5)=-2m(14m+11)-32

We move all terms to the left:

(2m+5)(m-5)-(-2m(14m+11)-32)=0

We multiply parentheses ..

(+2m^2-10m+5m-25)-(-2m(14m+11)-32)=0



We calculate terms in parentheses: -(-2m(14m+11)-32), so:

-2m(14m+11)-32

We multiply parentheses

-28m^2-22m-32

Back to the equation:

-(-28m^2-22m-32)



We get rid of parentheses

2m^2+28m^2-10m+5m+22m-25+32=0

We add all the numbers together, and all the variables

30m^2+17m+7=0

a = 30; b = 17; c = +7;
Δ = b2-4ac
Δ = 172-4·30·7
Δ = -551
Delta is less than zero, so there is no solution for the equation

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