n(180-2n)=0

Solution for n(180-2n)=0 equation:

n(180-2n)=0

We add all the numbers together, and all the variables

n(-2n+180)=0

We multiply parentheses

-2n^2+180n=0

a = -2; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·(-2)·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*-2}=\frac{-360}{-4}
=+90
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*-2}=\frac{0}{-4}
=0
$