3(x-1)=4(1+x)+13

Solution for 3(x-1)=4(1+x)+13 equation:

3(x-1)=4(1+x)+13

We move all terms to the left:

3(x-1)-(4(1+x)+13)=0

We add all the numbers together, and all the variables

3(x-1)-(4(x+1)+13)=0

We multiply parentheses

3x-(4(x+1)+13)-3=0


We calculate terms in parentheses: -(4(x+1)+13), so:

4(x+1)+13

We multiply parentheses

4x+4+13

We add all the numbers together, and all the variables

4x+17

Back to the equation:

-(4x+17)


We get rid of parentheses

3x-4x-17-3=0

We add all the numbers together, and all the variables

-1x-20=0

We move all terms containing x to the left, all other terms to the right

-x=20

x=20/-1

x=-20