5(y-4)-2(y-3)=12

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Solution for 5(y-4)-2(y-3)=12 equation: 



5(y-4)-2(y-3)=12

We move all terms to the left:

5(y-4)-2(y-3)-(12)=0

We multiply parentheses

5y-2y-20+6-12=0

We add all the numbers together, and all the variables

3y-26=0

We move all terms containing y to the left, all other terms to the right

3y=26

y=26/3

y=8+2/3

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