m-2(7+3m)=5(2m-3)-m-8

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Solution for m-2(7+3m)=5(2m-3)-m-8 equation: 



m-2(7+3m)=5(2m-3)-m-8

We move all terms to the left:

m-2(7+3m)-(5(2m-3)-m-8)=0

We add all the numbers together, and all the variables

m-2(3m+7)-(5(2m-3)-m-8)=0

We multiply parentheses

m-6m-(5(2m-3)-m-8)-14=0



We calculate terms in parentheses: -(5(2m-3)-m-8), so:

5(2m-3)-m-8

We add all the numbers together, and all the variables

-1m+5(2m-3)-8

We multiply parentheses

-1m+10m-15-8

We add all the numbers together, and all the variables

9m-23

Back to the equation:

-(9m-23)



We add all the numbers together, and all the variables

-5m-(9m-23)-14=0

We get rid of parentheses

-5m-9m+23-14=0

We add all the numbers together, and all the variables

-14m+9=0

We move all terms containing m to the left, all other terms to the right

-14m=-9

m=-9/-14

m=9/14

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