5(p+3)+p=3(p-2)

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Solution for 5(p+3)+p=3(p-2) equation: 



5(p+3)+p=3(p-2)

We move all terms to the left:

5(p+3)+p-(3(p-2))=0

We add all the numbers together, and all the variables

p+5(p+3)-(3(p-2))=0

We multiply parentheses

p+5p-(3(p-2))+15=0



We calculate terms in parentheses: -(3(p-2)), so:

3(p-2)

We multiply parentheses

3p-6

Back to the equation:

-(3p-6)



We add all the numbers together, and all the variables

6p-(3p-6)+15=0

We get rid of parentheses

6p-3p+6+15=0

We add all the numbers together, and all the variables

3p+21=0

We move all terms containing p to the left, all other terms to the right

3p=-21

p=-21/3

p=-7

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