2(2n-2)=4(n-2)

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Solution for 2(2n-2)=4(n-2) equation: 



2(2n-2)=4(n-2)

We move all terms to the left:

2(2n-2)-(4(n-2))=0

We multiply parentheses

4n-(4(n-2))-4=0



We calculate terms in parentheses: -(4(n-2)), so:

4(n-2)

We multiply parentheses

4n-8

Back to the equation:

-(4n-8)



We get rid of parentheses

4n-4n+8-4=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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