(2-3i)(1-2i)=0

Solution for (2-3i)(1-2i)=0 equation:

(2-3i)(1-2i)=0

We add all the numbers together, and all the variables

(-3i+2)(-2i+1)=0

We multiply parentheses ..

(+6i^2-3i-4i+2)=0

We get rid of parentheses

6i^2-3i-4i+2=0

We add all the numbers together, and all the variables

6i^2-7i+2=0

a = 6; b = -7; c = +2;
Δ = b2-4ac
Δ = -72-4·6·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*6}=\frac{6}{12}
=1/2
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*6}=\frac{8}{12}
=2/3
$