k+3/1-(3k-4)=-3/2

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Solution for k+3/1-(3k-4)=-3/2 equation: 



k+3/1-(3k-4)=-3/2

We move all terms to the left:

k+3/1-(3k-4)-(-3/2)=0

We add all the numbers together, and all the variables

k-(3k-4)-(-3/2)=0

We get rid of parentheses

k-3k+4+3/2=0

We multiply all the terms by the denominator


k*2-3k*2+3+4*2=0

We add all the numbers together, and all the variables

k*2-3k*2+11=0

Wy multiply elements

2k-6k+11=0

We add all the numbers together, and all the variables

-4k+11=0

We move all terms containing k to the left, all other terms to the right

-4k=-11

k=-11/-4

k=2+3/4

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