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6x(x+8)=132
We move all terms to the left:
6x(x+8)-(132)=0
We multiply parentheses
6x^2+48x-132=0
a = 6; b = 48; c = -132;
Δ = b2-4ac
Δ = 482-4·6·(-132)
Δ = 5472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5472}=\sqrt{144*38}=\sqrt{144}*\sqrt{38}=12\sqrt{38}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-12\sqrt{38}}{2*6}=\frac{-48-12\sqrt{38}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+12\sqrt{38}}{2*6}=\frac{-48+12\sqrt{38}}{12} $
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