k(2-4)-3=7k+4

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Solution for k(2-4)-3=7k+4 equation: 



k(2-4)-3=7k+4

We move all terms to the left:

k(2-4)-3-(7k+4)=0

We add all the numbers together, and all the variables

k(-2)-(7k+4)-3=0

We multiply parentheses

-2k-(7k+4)-3=0

We get rid of parentheses

-2k-7k-4-3=0

We add all the numbers together, and all the variables

-9k-7=0

We move all terms containing k to the left, all other terms to the right

-9k=7

k=7/-9

k=-7/9

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