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4/5t-1=1/5(t+25)
We move all terms to the left:
4/5t-1-(1/5(t+25))=0
Domain of the equation: 5t!=0
t!=0/5
t!=0
t∈R
Domain of the equation: 5(t+25))!=0We calculate fractions
t∈R
(20tt/(25t^2t+(-(1*5t)/(25t^2t-1=0
We can not solve this equation
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