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(1/5x)+4=5-(2/7x)
We move all terms to the left:
(1/5x)+4-(5-(2/7x))=0
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 7x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/5x)-(5-(+2/7x))+4=0
We get rid of parentheses
1/5x-(5-(+2/7x))+4=0
We calculate fractions
7x/35x^2+(-(5-(+2*5x)/35x^2+4=0
We calculate fractions
We do not support expression: x^4
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