h(-2)=2(-2)+3-2(-2)-5

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Solution for h(-2)=2(-2)+3-2(-2)-5 equation: 



h(-2)=2(-2)+3-2(-2)-5

We move all terms to the left:

h(-2)-(2(-2)+3-2(-2)-5)=0

We add all the numbers together, and all the variables

h(-2)+2=0

We multiply parentheses

-2h+2=0

We move all terms containing h to the left, all other terms to the right

-2h=-2

h=-2/-2

h=1

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