5(4f-3)+1=6

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Solution for 5(4f-3)+1=6 equation: 



5(4f-3)+1=6

We move all terms to the left:

5(4f-3)+1-(6)=0

We add all the numbers together, and all the variables

5(4f-3)-5=0

We multiply parentheses

20f-15-5=0

We add all the numbers together, and all the variables

20f-20=0

We move all terms containing f to the left, all other terms to the right

20f=20

f=20/20

f=1

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