7(r-2)-9(r-1)=3(5-r)+(r+8)

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Solution for 7(r-2)-9(r-1)=3(5-r)+(r+8) equation: 



7(r-2)-9(r-1)=3(5-r)+(r+8)

We move all terms to the left:

7(r-2)-9(r-1)-(3(5-r)+(r+8))=0

We add all the numbers together, and all the variables

7(r-2)-9(r-1)-(3(-1r+5)+(r+8))=0

We multiply parentheses

7r-9r-(3(-1r+5)+(r+8))-14+9=0



We calculate terms in parentheses: -(3(-1r+5)+(r+8)), so:

3(-1r+5)+(r+8)

We multiply parentheses

-3r+(r+8)+15

We get rid of parentheses

-3r+r+8+15

We add all the numbers together, and all the variables

-2r+23

Back to the equation:

-(-2r+23)



We add all the numbers together, and all the variables

-2r-(-2r+23)-5=0

We get rid of parentheses

-2r+2r-23-5=0

We add all the numbers together, and all the variables

-28!=0

There is no solution for this equation

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