1/4(13y-3)+1/8(6y+9=0

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Solution for 1/4(13y-3)+1/8(6y+9=0 equation: 



1/4(13y-3)+1/8(6y+9=0



Domain of the equation: 4(13y-3)!=0

y∈R





Domain of the equation: 8(6y+9!=0

y∈R



We calculate fractions


(8y6/(4(13y-3)*8(6y+9)+(4y1/(4(13y-3)*8(6y+9)=0



We calculate terms in parentheses: +(8y6/(4(13y-3)*8(6y+9)+(4y1/(4(13y-3)*8(6y+9), so:

8y6/(4(13y-3)*8(6y+9)+(4y1/(4(13y-3)*8(6y+9

We can not solve this equation

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