10-4(3-2y)=23-(2y-1)

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Solution for 10-4(3-2y)=23-(2y-1) equation: 



10-4(3-2y)=23-(2y-1)

We move all terms to the left:

10-4(3-2y)-(23-(2y-1))=0

We add all the numbers together, and all the variables

-4(-2y+3)-(23-(2y-1))+10=0

We multiply parentheses

8y-(23-(2y-1))-12+10=0



We calculate terms in parentheses: -(23-(2y-1)), so:

23-(2y-1)

determiningTheFunctionDomain
-(2y-1)+23

We get rid of parentheses

-2y+1+23

We add all the numbers together, and all the variables

-2y+24

Back to the equation:

-(-2y+24)



We add all the numbers together, and all the variables

8y-(-2y+24)-2=0

We get rid of parentheses

8y+2y-24-2=0

We add all the numbers together, and all the variables

10y-26=0

We move all terms containing y to the left, all other terms to the right

10y=26

y=26/10

y=2+3/5

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