f-((3f-2)/3)=1/12

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Solution for f-((3f-2)/3)=1/12 equation: 



f-((3f-2)/3)=1/12

We move all terms to the left:

f-((3f-2)/3)-(1/12)=0

We add all the numbers together, and all the variables

f-((3f-2)/3)-(+1/12)=0

We get rid of parentheses

f-((3f-2)/3)-1/12=0

We calculate fractions


f+(-((3f-2)*12)/()+()/()=0



We calculate terms in parentheses: +(-((3f-2)*12)/()+()/(), so:

-((3f-2)*12)/()+()/(

We add all the numbers together, and all the variables

-((3f-2)*12)/()+1

We multiply all the terms by the denominator


-((3f-2)*12)+1*()



We calculate terms in parentheses: -((3f-2)*12), so:

(3f-2)*12

We multiply parentheses

36f-24

Back to the equation:

-(36f-24)



We add all the numbers together, and all the variables

-(36f-24)

We get rid of parentheses

-36f+24

Back to the equation:

+(-36f+24)



We get rid of parentheses

f-36f+24=0

We add all the numbers together, and all the variables

-35f+24=0

We move all terms containing f to the left, all other terms to the right

-35f=-24

f=-24/-35

f=24/35

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