(x+2)+5(x-1)=3(x+3)

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Solution for (x+2)+5(x-1)=3(x+3) equation: 



(x+2)+5(x-1)=3(x+3)

We move all terms to the left:

(x+2)+5(x-1)-(3(x+3))=0

We multiply parentheses

(x+2)+5x-(3(x+3))-5=0

We get rid of parentheses

x+5x-(3(x+3))+2-5=0



We calculate terms in parentheses: -(3(x+3)), so:

3(x+3)

We multiply parentheses

3x+9

Back to the equation:

-(3x+9)



We add all the numbers together, and all the variables

6x-(3x+9)-3=0

We get rid of parentheses

6x-3x-9-3=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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