f(-2)=f(2)=

Solution for f(-2)=f(2)= equation:

f(-2)=f(2)=

We move all terms to the left:

f(-2)-(f(2))=0

determiningTheFunctionDomain
f(-2)-f2=0

We add all the numbers together, and all the variables

-1f^2+f(-2)=0

We multiply parentheses

-1f^2-2f=0

a = -1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-1}=\frac{0}{-2}
=0
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-1}=\frac{4}{-2}
=-2
$