(x+2)=3(x-5)-7(x+3)

Solution for (x+2)=3(x-5)-7(x+3) equation:

(x+2)=3(x-5)-7(x+3)

We move all terms to the left:

(x+2)-(3(x-5)-7(x+3))=0

We get rid of parentheses

x-(3(x-5)-7(x+3))+2=0


We calculate terms in parentheses: -(3(x-5)-7(x+3)), so:

3(x-5)-7(x+3)

We multiply parentheses

3x-7x-15-21

We add all the numbers together, and all the variables

-4x-36

Back to the equation:

-(-4x-36)


We get rid of parentheses

x+4x+36+2=0

We add all the numbers together, and all the variables

5x+38=0

We move all terms containing x to the left, all other terms to the right

5x=-38

x=-38/5

x=-7+3/5