x(4x-3)=8x2-1

Solution for x(4x-3)=8x2-1 equation:

x(4x-3)=8x^2-1

We move all terms to the left:

x(4x-3)-(8x^2-1)=0

We multiply parentheses

4x^2-3x-(8x^2-1)=0

We get rid of parentheses

4x^2-8x^2-3x+1=0

We add all the numbers together, and all the variables

-4x^2-3x+1=0

a = -4; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·(-4)·1
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-5}{2*-4}=\frac{-2}{-8}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+5}{2*-4}=\frac{8}{-8}
=-1
$