c2-50=-23c

Solution for c2-50=-23c equation:

c2-50=-23c

We move all terms to the left:

c2-50-(-23c)=0

We add all the numbers together, and all the variables

c^2-(-23c)-50=0

We get rid of parentheses

c^2+23c-50=0

a = 1; b = 23; c = -50;
Δ = b2-4ac
Δ = 232-4·1·(-50)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-27}{2*1}=\frac{-50}{2}
=-25
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+27}{2*1}=\frac{4}{2}
=2
$