(2/3x)+1=1/6x-7

Solution for (2/3x)+1=1/6x-7 equation:

(2/3x)+1=1/6x-7

We move all terms to the left:

(2/3x)+1-(1/6x-7)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 6x-7)!=0

x∈R


We add all the numbers together, and all the variables

(+2/3x)-(1/6x-7)+1=0

We get rid of parentheses

2/3x-1/6x+7+1=0

We calculate fractions


12x/18x^2+(-3x)/18x^2+7+1=0

We add all the numbers together, and all the variables

12x/18x^2+(-3x)/18x^2+8=0

We multiply all the terms by the denominator


12x+(-3x)+8*18x^2=0

Wy multiply elements

144x^2+12x+(-3x)=0

We get rid of parentheses

144x^2+12x-3x=0

We add all the numbers together, and all the variables

144x^2+9x=0

a = 144; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·144·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*144}=\frac{-18}{288}
=-1/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*144}=\frac{0}{288}
=0
$