(10-4x/3)+(6x-5/2)=1/6

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Solution for (10-4x/3)+(6x-5/2)=1/6 equation: 



(10-4x/3)+(6x-5/2)=1/6

We move all terms to the left:

(10-4x/3)+(6x-5/2)-(1/6)=0

We add all the numbers together, and all the variables

(-4x/3+10)+(+6x-5/2)-(+1/6)=0

We get rid of parentheses

-4x/3+6x+10-5/2-1/6=0

We calculate fractions

There is no solution for this equation

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