7/5(3+x)=2

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Solution for 7/5(3+x)=2 equation: 



7/5(3+x)=2

We move all terms to the left:

7/5(3+x)-(2)=0



Domain of the equation: 5(3+x)!=0

x∈R



We add all the numbers together, and all the variables

7/5(x+3)-2=0

We multiply all the terms by the denominator


-2*5(x+3)+7=0

Wy multiply elements

-10x(x+7=0

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