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b=9/b-(-10)
We move all terms to the left:
b-(9/b-(-10))=0
Domain of the equation: b-(-10))!=0We multiply all the terms by the denominator
b∈R
b*b-(-10))-(9=0
We add all the numbers together, and all the variables
b*b=0
Wy multiply elements
b^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{0}{2}=0$
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