7(1+3a)=7a+35

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Solution for 7(1+3a)=7a+35 equation: 



7(1+3a)=7a+35

We move all terms to the left:

7(1+3a)-(7a+35)=0

We add all the numbers together, and all the variables

7(3a+1)-(7a+35)=0

We multiply parentheses

21a-(7a+35)+7=0

We get rid of parentheses

21a-7a-35+7=0

We add all the numbers together, and all the variables

14a-28=0

We move all terms containing a to the left, all other terms to the right

14a=28

a=28/14

a=2

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