100(z-0.2)=-10(5z+8)

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Solution for 100(z-0.2)=-10(5z+8) equation: 



100(z-0.2)=-10(5z+8)

We move all terms to the left:

100(z-0.2)-(-10(5z+8))=0

We multiply parentheses

100z-(-10(5z+8))-20=0



We calculate terms in parentheses: -(-10(5z+8)), so:

-10(5z+8)

We multiply parentheses

-50z-80

Back to the equation:

-(-50z-80)



We get rid of parentheses

100z+50z+80-20=0

We add all the numbers together, and all the variables

150z+60=0

We move all terms containing z to the left, all other terms to the right

150z=-60

z=-60/150

z=-2/5

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