1000(8q-10)=40(780+1000q)

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Solution for 1000(8q-10)=40(780+1000q) equation: 



1000(8q-10)=40(780+1000q)

We move all terms to the left:

1000(8q-10)-(40(780+1000q))=0

We add all the numbers together, and all the variables

1000(8q-10)-(40(1000q+780))=0

We multiply parentheses

8000q-(40(1000q+780))-10000=0



We calculate terms in parentheses: -(40(1000q+780)), so:

40(1000q+780)

We multiply parentheses

40000q+31200

Back to the equation:

-(40000q+31200)



We get rid of parentheses

8000q-40000q-31200-10000=0

We add all the numbers together, and all the variables

-32000q-41200=0

We move all terms containing q to the left, all other terms to the right

-32000q=41200

q=41200/-32000

q=-1+23/80

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