-8(1+n)-2n=-8+4(1-3n)

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Solution for -8(1+n)-2n=-8+4(1-3n) equation: 



-8(1+n)-2n=-8+4(1-3n)

We move all terms to the left:

-8(1+n)-2n-(-8+4(1-3n))=0

We add all the numbers together, and all the variables

-8(n+1)-2n-(-8+4(-3n+1))=0

We add all the numbers together, and all the variables

-2n-8(n+1)-(-8+4(-3n+1))=0

We multiply parentheses

-2n-8n-(-8+4(-3n+1))-8=0



We calculate terms in parentheses: -(-8+4(-3n+1)), so:

-8+4(-3n+1)

determiningTheFunctionDomain
4(-3n+1)-8

We multiply parentheses

-12n+4-8

We add all the numbers together, and all the variables

-12n-4

Back to the equation:

-(-12n-4)



We add all the numbers together, and all the variables

-10n-(-12n-4)-8=0

We get rid of parentheses

-10n+12n+4-8=0

We add all the numbers together, and all the variables

2n-4=0

We move all terms containing n to the left, all other terms to the right

2n=4

n=4/2

n=2

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