4c-3=6(3-c)-4

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Solution for 4c-3=6(3-c)-4 equation: 



4c-3=6(3-c)-4

We move all terms to the left:

4c-3-(6(3-c)-4)=0

We add all the numbers together, and all the variables

4c-(6(-1c+3)-4)-3=0



We calculate terms in parentheses: -(6(-1c+3)-4), so:

6(-1c+3)-4

We multiply parentheses

-6c+18-4

We add all the numbers together, and all the variables

-6c+14

Back to the equation:

-(-6c+14)



We get rid of parentheses

4c+6c-14-3=0

We add all the numbers together, and all the variables

10c-17=0

We move all terms containing c to the left, all other terms to the right

10c=17

c=17/10

c=1+7/10

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