a=2a+4/5(a+3a)

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Solution for a=2a+4/5(a+3a) equation: 



a=2a+4/5(a+3a)

We move all terms to the left:

a-(2a+4/5(a+3a))=0



Domain of the equation: 5(a+3a))!=0

a∈R



We add all the numbers together, and all the variables

a-(2a+4/5(+4a))=0

We multiply all the terms by the denominator


a*5(+4a))-(2a+4=0

Wy multiply elements

5a^2(++4=0

We use the square of the difference formula

5a^2(+4=0

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