((7x-3)/3)-((4x+2)/2)+((5-3x)/8)=3

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Solution for ((7x-3)/3)-((4x+2)/2)+((5-3x)/8)=3 equation: 



((7x-3)/3)-((4x+2)/2)+((5-3x)/8)=3

We move all terms to the left:

((7x-3)/3)-((4x+2)/2)+((5-3x)/8)-(3)=0

We add all the numbers together, and all the variables

((7x-3)/3)-((4x+2)/2)+((-3x+5)/8)-3=0

We calculate fractions


56x/()+(-32x)/()+(-6x)/()-3=0

We multiply all the terms by the denominator


56x+(-32x)+(-6x)-3*()=0

We add all the numbers together, and all the variables

56x+(-32x)+(-6x)=0

We get rid of parentheses

56x-32x-6x=0

We add all the numbers together, and all the variables

18x=0

x=0/18

x=0

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