x2+54x=1296

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Solution for x2+54x=1296 equation:



x2+54x=1296
We move all terms to the left:
x2+54x-(1296)=0
We add all the numbers together, and all the variables
x^2+54x-1296=0
a = 1; b = 54; c = -1296;
Δ = b2-4ac
Δ = 542-4·1·(-1296)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-90}{2*1}=\frac{-144}{2} =-72 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+90}{2*1}=\frac{36}{2} =18 $

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