Z+15=(z+2z-36)/2

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Solution for Z+15=(z+2z-36)/2 equation: 



+15=(Z+2Z-36)/2

We move all terms to the left:

+15-((Z+2Z-36)/2)=0

We add all the numbers together, and all the variables

-((3Z-36)/2)+15=0

We multiply all the terms by the denominator


-((3Z-36)+15*2)=0



We calculate terms in parentheses: -((3Z-36)+15*2), so:

(3Z-36)+15*2

We add all the numbers together, and all the variables

(3Z-36)+30

We get rid of parentheses

3Z-36+30

We add all the numbers together, and all the variables

3Z-6

Back to the equation:

-(3Z-6)



We get rid of parentheses

-3Z+6=0

We move all terms containing Z to the left, all other terms to the right

-3Z=-6

Z=-6/-3

Z=+2

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