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=A2+7A+10
We move all terms to the left:
-(A2+7A+10)=0
We add all the numbers together, and all the variables
-(+A^2+7A+10)=0
We get rid of parentheses
-A^2-7A-10=0
We add all the numbers together, and all the variables
-1A^2-7A-10=0
a = -1; b = -7; c = -10;
Δ = b2-4ac
Δ = -72-4·(-1)·(-10)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-3}{2*-1}=\frac{4}{-2} =-2 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+3}{2*-1}=\frac{10}{-2} =-5 $
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