Z+15=(z+2z-36)

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Solution for Z+15=(z+2z-36) equation: 



+15=(Z+2Z-36)

We move all terms to the left:

+15-((Z+2Z-36))=0

We add all the numbers together, and all the variables

-((3Z-36))+15=0



We calculate terms in parentheses: -((3Z-36)), so:

(3Z-36)

We get rid of parentheses

3Z-36

Back to the equation:

-(3Z-36)



We get rid of parentheses

-3Z+36+15=0

We add all the numbers together, and all the variables

-3Z+51=0

We move all terms containing Z to the left, all other terms to the right

-3Z=-51

Z=-51/-3

Z=+17

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