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=Y(2)+5
We move all terms to the left:
-(Y(2)+5)=0
We add all the numbers together, and all the variables
-(+Y^2+5)=0
We get rid of parentheses
-Y^2-5=0
We add all the numbers together, and all the variables
-1Y^2-5=0
a = -1; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-1)·(-5)
Δ = -20
Delta is less than zero, so there is no solution for the equation
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