(3x-2)3=(x+1)20

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Solution for (3x-2)3=(x+1)20 equation: 



(3x-2)3=(x+1)20

We move all terms to the left:

(3x-2)3-((x+1)20)=0

We multiply parentheses

9x-((x+1)20)-6=0



We calculate terms in parentheses: -((x+1)20), so:

(x+1)20

We multiply parentheses

20x+20

Back to the equation:

-(20x+20)



We get rid of parentheses

9x-20x-20-6=0

We add all the numbers together, and all the variables

-11x-26=0

We move all terms containing x to the left, all other terms to the right

-11x=26

x=26/-11

x=-2+4/11

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