(3x+1)4=(x+3)15

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Solution for (3x+1)4=(x+3)15 equation: 



(3x+1)4=(x+3)15

We move all terms to the left:

(3x+1)4-((x+3)15)=0

We multiply parentheses

12x-((x+3)15)+4=0



We calculate terms in parentheses: -((x+3)15), so:

(x+3)15

We multiply parentheses

15x+45

Back to the equation:

-(15x+45)



We get rid of parentheses

12x-15x-45+4=0

We add all the numbers together, and all the variables

-3x-41=0

We move all terms containing x to the left, all other terms to the right

-3x=41

x=41/-3

x=-13+2/3

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